Theory & Concepts
SSC CGL Work and Wages Questions, Formulas & Tricks
Prepare Work and Wages for SSC CGL with formulas, short tricks, solved examples, practice questions, PYQs, and free PDF notes for faster exam preparation.
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Practice Notes
15 min readDifficulty: Intermediate
Work and wages is a practical application of the time and work chapter. The most important rule to remember here is that wages are distributed based on the work done by each person, not the time spent.
In the Ssc cgl exam, questions often involve multiple people with different efficiencies receiving a combined sum. We will master how to use efficiency ratios to split these sums in seconds.
Learning path
- The efficiency-wage rule
- Splitting wages between groups
- Ratio-based wage division
- 10 standard solved problems
- Previous year patterns
1. Calculation logic
Crucial Note:
If all persons work for the **same number of days**, then the wages are distributed according to their **efficiency ratio** alone.
2. Solved examples
Question 01Standard pattern
A can do a piece of work in 10 days and B in 15 days. They work together and receive rs. 3,000 for the whole work. What is A's share?
rs. 1,800
rs. 1,200
rs. 1,500
rs. 2,000
Correct answer: a) rs. 1,800
Solution
LCM of 10 and 15 = \( 30 \text{ units} (Total Work) \).
Efficiency of A = \( 30 / 10 = 3 \text{ units/day} \).
Efficiency of B = \( 30 / 15 = 2 \text{ units/day} \).
Since they work together for same time, Wage Ratio = Efficiency Ratio = \( 3 : 2 \).
Share of A = \( \frac{3}{5} \times 3000 = rs. 1,800 \).
Question 02Standard pattern
A, B and C are employed to do a work for rs. 529. A and B together do 19/23 of the work. How much should C be paid?
rs. 92
rs. 80
rs. 100
rs. 110
Correct answer: a) rs. 92
Solution
Total work = \( 1 \text{ unit} \).
Work done by (A+B) = \( 19/23 \).
Work done by C = \( 1 - 19/23 = 4/23 \).
Payment for C = \( \frac{4}{23} \times 529 \).
Calculation: \( 4 \times 23 = 92 \).
Result = \( rs. 92 \).
Question 03Standard pattern
A, B and C take a contract for rs. 440. A and B together do 9/11 of the work. What is the share of C?
rs. 80
rs. 40
rs. 90
rs. 100
Correct answer: a) rs. 80
Solution
Work of (A+B) = \( 9/11 \). Remaining work of C = \( 1 - 9/11 = 2/11 \).
Share of C = \( \frac{2}{11} \times 440 = 2 \times 40 = rs. 80 \).
Question 04Standard pattern
A can do a work in 6 days and B in 8 days. They took the work for rs. 3,200. With the help of C, they completed the work in 3 days. What is C's share?
rs. 400
rs. 600
rs. 800
rs. 500
Correct answer: a) rs. 400
Solution
LCM of 6 and 8 = \( 24 \text{ units} \).
Efficiency of A = \( 24/6 = 4 \). Efficiency of B = \( 24/8 = 3 \).
Since (A+B+C) finished in 3 days, their combined efficiency = \( 24 / 3 = 8 \).
Efficiency of C = \( 8 - (4 + 3) = 1 \).
Wage Ratio A : B : C = \( 4 : 3 : 1 \).
Share of C = \( \frac{1}{8} \times 3200 = rs. 400 \).
Question 05Standard pattern
Daily wages of A and B are rs. 3.50 and rs. 2.50 respectively. A finishes a work in 20 days. How much would B receive for finishing the same work?
rs. 70
rs. 50
rs. 60
rs. 80
Correct answer: a) rs. 70
Solution
Since wages are for a particular work, let's assume total work is 20 days of A.
Actually, if A finishes in 20 days, his total pay = \( 20 \times 3.50 = rs. 70 \).
Since they are employed for the *same work*, B would receive the same amount for completing it.
Result = \( rs. 70 \).
Question 06Standard pattern
A, B and C can do a work in 10, 15 and 20 days respectively. They finished together and got rs. 2,600. B's share is:
rs. 800
rs. 600
rs. 1,000
rs. 1,200
Correct answer: a) rs. 800
Solution
LCM of 10, 15, 20 = \( 60 \).
Efficiencies: \( A=6, B=4, C=3 \).
Ratio of wages = \( 6 : 4 : 3 \).
Total parts = \( 13 \).
Share of B = \( \frac{4}{13} \times 2600 = 4 \times 200 = rs. 800 \).
Question 07Standard pattern
A can do a work in 15 days and B in 20 days. C joins and they finish in 5 days for rs. 1,200. Find A's share.
rs. 400
rs. 300
rs. 500
rs. 200
Correct answer: a) rs. 400
Solution
A's 1-day work = \( 1/15 \). In 5 days, A does \( 5/15 = 1/3 \) of the work.
Since wages follow work done: Share of A = \( \frac{1}{3} \times 1200 = rs. 400 \).
Question 08Standard pattern
A, B, C can do work in 4, 6 and 10 days respectively. They finish together for rs. 620. What is the difference between A and C's share?
rs. 180
rs. 150
rs. 200
rs. 120
Correct answer: a) rs. 180
Solution
LCM (4, 6, 10) = \( 60 \).
Efficiencies: \( A=15, B=10, C=6 \).
Total: \( 31 \text{ parts} \). Multiplier: \( 620/31 = 20 \).
Difference (A-C) in parts: \( 15 - 6 = 9 \).
Calculation: \( 9 \times 20 = rs. 180 \).
Question 09Standard pattern
If 10 men earn rs. 1,500 in 15 days, how much will 12 men earn in 10 days?
rs. 1,200
rs. 1,000
rs. 1,500
rs. 900
Correct answer: a) rs. 1,200
Solution
Use Chain Rule: \( \frac{M_1 D_1}{W_1} = \frac{M_2 D_2}{W_2} \).
Substitute: \( \frac{10 \times 15}{1500} = \frac{12 \times 10}{W_2} \).
\( \frac{150}{1500} = \frac{120}{W_2} \implies \frac{1}{10} = \frac{120}{W_2} \).
Result: \( W_2 = rs. 1,200 \).
Question 010Standard pattern
A and B alone can finish work in 10 days and 15 days. If total wage is rs. 4,500, but they worked for only 2 days together and left. How much did they earn?
rs. 1,500
rs. 1,000
rs. 2,000
rs. 1,200
Correct answer: a) rs. 1,500
Solution
Combined 1-day work = \( 1/10 + 1/15 = 5/30 = 1/6 \).
Work in 2 days = \( 2/6 = 1/3 \).
Wages for work done = \( \frac{1}{3} \times 4500 = rs. 1,500 \).