Theory & Concepts

SSC CGL Successive Percentage Change Questions & Tricks

Prepare Successive Percentage Change for SSC CGL with formulas, short tricks, solved examples, practice questions, PYQs, and free PDF notes for faster exam preparation.

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20 min readDifficulty: Intermediate

Successive percentage change is the engine behind Compound Interest, Population Growth, and Depreciation. Mastering this tool allows you to bypass multi-step calculations with a single formula.

Whether it's a 2D area change or a 3D volume shift, the ratio-based "AB Formula" provides the fastest route to the final answer in Ssc cgl Tier-1 and Tier-2 exams.

Learning path

  • The master AB formula
  • 3D Volume (iterative) logic
  • Equivalent discount shortcut
  • 10 standard solved problems
  • Fractional percentage ratio method

1. The AB Formula (2-Step Change)

If a quantity changes by a%a\% and then by b%b\%, the net percentage change is:

Net Change %=a+b+ab100\text{Net Change \%} = a + b + \frac{ab}{100}

Important Rule:

  • Use positive (+) value for increase/profit.
  • Use negative (-) value for decrease/discount.

2. The 3D iterative logic (Volume)

For 3rd degree shifts (like volume of a sphere or cylinder), apply the formula twice:

Step 1: Apply formula to first two changes to get X%X\%.

Step 2: Apply formula between X%X\% and the third change.

Example: 10% increase in sphere radius. Step 1: 10 + 10 + 1 = 21%. Step 2: 21 + 10 + 2.1 = 33.1%.

3. 10 Solved examples

Question 01Standard pattern

Salary of a person was increased by 20% and then decreased by 20%. Find his net salary change.

4% decrease
4% increase
No change
1% decrease
Correct answer: a) 4% decrease

Solution

Here \( a = 20 \) and \( b = -20 \).
Net change = \( 20 - 20 + \frac{20 \times (-20)}{100} \).
Calculation: \( 0 - 4 = -4\% \).
Result = \( 4\% \text{ decrease} \).
Question 02Standard pattern

What is a single discount equivalent to two successive discounts of 20% and 10%?

28%
30%
25%
26%
Correct answer: a) 28%

Solution

For discount, use negative values: \( a = -20, b = -10 \).
Calculation: \( -20 - 10 + \frac{(-20) \times (-10)}{100} \).
Result: \( -30 + 2 = -28\% \).
Question 03Standard pattern

The length and breadth of a rectangle are increased by 20% and 30% respectively. Find percentage increase in area.

56%
50%
60%
44%
Correct answer: a) 56%

Solution

Calculation: \( 20 + 30 + (20 \times 30)/100 = 50 + 6 = 56\% \).
Question 04Standard pattern

The radius of a sphere is increased by 10%. What is the percentage increase in its volume?

33.1%
21%
30%
31%
Correct answer: a) 33.1%

Solution

Volume depends on \( r^3 \). We need three iterations of 10%.
Step 1 (Area): \( 10 + 10 + 1 = 21\% \).
Step 2 (Volume): \( 21 + 10 + (21 \times 10)/100 = 33.1\% \).
Question 05Standard pattern

The price of sugar is increased by 32%. A family reduces consumption so that expenditure increases by only 10%. If current consumption is 30 kg, find original consumption.

36 kg
35 kg
40 kg
32 kg
Correct answer: a) 36 kg

Solution

Formula: \( \frac{C_1}{C_2} = \frac{100 + E%}{100 + P%} \)? No, Ratio Method is better.
Price Ratio: \( 100 : 132 \). Exp Ratio: \( 100 : 110 \).
Cons Ratio = \( Exp / Price = 110 / 132 = 5/6 \).
Current (5 units) = 30 kg. 1 unit = 6 kg.
Original (6 units) = \( 6 \times 6 = 36 \text{ kg} \).
Question 06Standard pattern

Length of a rectangle increases by 10% and area increases by 21%. Find change in breadth.

10% increase
11% increase
5% increase
12% increase
Correct answer: a) 10% increase

Solution

Eq: \( 10 + x + 10x/100 = 21 \).
\( 1.1x = 11 \implies x = 10 \).
Question 07Standard pattern

Side of a cube is increased by 50%. Find percentage increase in volume.

237.5%
125%
150%
225%
Correct answer: a) 237.5%

Solution

Apply 50% three times.
Step 1: \( 50 + 50 + 25 = 125\% \).
Step 2: \( 125 + 50 + (125 \times 50)/100 = 175 + 62.5 = 237.5\% \).
Question 08Standard pattern

Radius of cone increased by 10% and height decreased by 20%. Net change in volume?

3.2% decrease
3.2% increase
5% decrease
No change
Correct answer: a) 3.2% decrease

Solution

\( r^2 \) change = 21% increase.
Volume with h: \( 21 - 20 - (21 \times 20)/100 = 1 - 4.2 = -3.2\% \).
Question 09Standard pattern

Equivalent single increase for successive increases of 20% and 25%.

50%
45%
60%
44%
Correct answer: a) 50%

Solution

Calculation: \( 20 + 25 + (20 \times 25)/100 = 45 + 5 = 50\% \).
Question 010Standard pattern

Population of a town is 10,000. It increases by 10% first yr and decreases by 10% second yr. Net population?

9,900
10,000
9,800
11,000
Correct answer: a) 9,900

Solution

Net change = 1% decrease.
Calculation: \( 0.99 \times 10000 = 9900 \).

4. Strategy errors to avoid

Error 01Addition trap: Adding 20% and 30% to get 50% instead of using the successive formula.
Error 02Negative oversight: Forgetting to put a minus (-) sign for discounts or decreases in the AB formula.
Error 03Volume neglect: Only calculating the area increase (r^2) when the question asks for volume increase (r^3).
Error 04Fractional delay: Using the AB formula for complex fractions like 16.66% instead of the Ratio Method.
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